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class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
hash_map = {}
for i, num in enumerate(nums):
diff = target - num
if diff in hash_map:
return [hash_map[diff], i]
hash_map[num] = i
return[]Time Complexity: O(N)
Space Complexity: O(N)
Optimal solution. Hash map stores visited elements allowing O(1) lookups.
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